beranekr I need to go sentence by sentence because we are starting running in circles here.
You just gave this article as a proof for the band bending. The article shows the opposite: that no band bending is needed and that my approach to the problem is valid. So, what do you agree with?
The concept of band bending is a direct consequence of the convention of solid state physics that requires that the Fermi level across an (electronically communicating) system in equllibrium is constant across the whole system (device).
The Fermi level is constant in a conductor in equilibrium. But I don’t see that the “band bending” results from that observation directly or otherwise.
In other words, the band bending is the consequence of the fact that - in a conventional energy diagram - the vacuum level is not a “straight line” but follows the spatial changes of electric potential (more accurately, of the so-called outer/Volta potential), i.e., the vacuum level will show the same bending like the bands.
And here you use the circular argument again: The bands bend because the vacuum level bends . Perhaps you can break the circle by explaining why does the vacuum level bend? And just stating that it “follows the spatial changes of electric potential” is no explanation because the vacuum level also originates from Schrödinger equation and can bend as much as any other quantum eigenvalue or a number $\pi$, for example.
The energy diagrams constructed in this way have proven very useful for generations of solid state physicists in order to explain the behavior of various devices.
By “very useful” you mean “commonly used”. Unfortunately, either way, it does not make them correct.
Footnote 1: When I speak about the vacuum level, I mean the so-called “local vacuum level”, that is the energy of an electron at rest (zero kinetic energy) “just outside” of the material. With respect to this “local” vacuum level all spectroscopy is measured, hence only this vacuum level is relevant; for details see this wonderful reference: https://www.theoechem.org/owncloud/index.php/s/ph6ueyJ6dClp3Eh
This time you fall into a trap of the Cahen and Kahn article and their “local vacuum level” notion.
First of all it is not a quantum level. It is some energy of an electron at rest inserted “by hand” by the authors.
Second, for finite-size samples, as authors describe it at the beginning of section 2, their proposition is impossible.
Namely, position for the resting electron does not exist.
The place is supposed to be far enough from the surface of the conductor, so that the image charge attraction has no effect. Still close enough so that the electron is affected by the electronic surface dipole. Those two conditions are impossible to be fulfilled simultaneously for any finite-size sample in 3-dimensional space. This is because the image charge potential decays like $\propto 1/r$ (Coulomb potential) while the surface dipole potential decays like $\propto 1/r^2$, where $r$ is the distance from the surface.
So, if the electron is far enough due to the image charge, there is no surface dipole potential anymore.
The reference is full of wonders indeed 🙂.